What is the limit as x approaches 0+of-4ln(x) ?

The limit as x approaches 0+of-4ln(x) is infinity

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limit as x approaches 0+of-4ln(x)

x \to 0 + lim (- 4 ln (x))

\infty

Solution steps

x \to 0 + lim (- 4 ln (x))

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - 4 \cdot x \to 0 + lim (ln (x))

Apply the common limit:

x \to 0 + lim (ln (x)) = - \infty

= - 4 (- \infty)

Apply Infinity Property:

- c \cdot (- \infty) = \infty

= \infty

x \to 0 + lim (x^{18 x})

x \to 0 lim (e^{- x} - 1)

x \to \frac{π}{2} - lim (sin (x))

x \to 0 lim (\frac{1}{x ^{2} + 3 x})

x \to 1 + lim ((8 x + \frac{2}{x})^{5})

What is the limit as x approaches 0+of-4ln(x) ?
The limit as x approaches 0+of-4ln(x) is infinity