What is the limit as x approaches 1+of g(x) ?

The limit as x approaches 1+of g(x) is g(1)

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limit as x approaches 1+of g(x)

x \to 1 + lim (g (x))

g (1)

Solution steps

x \to 1 + lim (g (x))

Plug in the value

x = 1

, assuming the function is continuous at this point

= g (1)

x \to - 4 lim (\frac{2 x}{6 x - 10})

x \to 1 lim ((x^{3} - 1)^{\frac{2}{3}})

t \to - 1 lim (\frac{t + 1}{∣ t + 1 ∣})

x \to 0 lim (\frac{5 x + sin ( x )}{x})

x \to 0 lim (x^{2} + 4 x)

What is the limit as x approaches 1+of g(x) ?
The limit as x approaches 1+of g(x) is g(1)