What is the limit as r approaches 0 of (sin(r))/r ?

The limit as r approaches 0 of (sin(r))/r is 1

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limit as r approaches 0 of (sin(r))/r

r \to 0 lim (\frac{sin ( r )}{r})

1

Solution steps

r \to 0 lim (\frac{sin ( r )}{r})

Apply L'Hopital's Rule

= r \to 0 lim (\frac{cos ( r )}{1})

Plug in the value

r = 0

= \frac{cos ( 0 )}{1}

Simplify

\frac{cos ( 0 )}{1} : 1

= 1

x \to 1 - lim (\frac{1}{1 - e ^{x - 1}})

t \to - \infty lim (t^{3} e^{t})

x \to 2 - lim (\frac{x ^{2} + 1}{x + 2})

x \to 0 lim (\frac{8 ^{x} - 3 ^{x}}{x})

x \to 0 lim (1 - \frac{3}{x}^{x})

What is the limit as r approaches 0 of (sin(r))/r ?
The limit as r approaches 0 of (sin(r))/r is 1