What is the limit as x approaches-1 of ln(x^2) ?

The limit as x approaches-1 of ln(x^2) is 0

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limit as x approaches-1 of ln(x^2)

x \to - 1 lim (ln (x^{2}))

0

Solution steps

x \to - 1 lim (ln (x^{2}))

Plug in the value

x = - 1

= ln ((- 1)^{2})

Simplify

ln ((- 1)^{2}) : 0

= 0

x \to \infty lim (\frac{8 x ^{2} - 3 x}{16 x ^{2} - 1})

x \to \infty lim ([3, x])

x \to - 2 lim (7 x + 1)

x \to \infty lim (\frac{2 x}{2})

x \to 0 lim (x sec (x))

What is the limit as x approaches-1 of ln(x^2) ?
The limit as x approaches-1 of ln(x^2) is 0