What is the integral of 1/(sqrt(2x-5)) ?

The integral of 1/(sqrt(2x-5)) is sqrt(2x-5)+C

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integral of 1/(sqrt(2x-5))

\int \frac{1}{2 x - 5} d x

2 x - 5 + C

Solution steps

\int \frac{1}{2 x - 5} d x

Apply u-substitution

= \int 1 d u

Integral of a constant:

\int a d x = a x

= 1 \cdot u

Substitute back

u = 2 x - 5

= 1 \cdot 2 x - 5

Simplify

= 2 x - 5

Add a constant to the solution

= 2 x - 5 + C

\frac{\partial}{\partial x} (2 zy)

a re a x = \frac{( y - 4 ) ^{2}}{4}, y = 7 - x

d er i v a t i v e ln (e^{3 x})

\frac{d}{d x} (\frac{x + 3}{x - 2})

\frac{\partial}{\partial x} (x y^{3} + 2 x y)

What is the integral of 1/(sqrt(2x-5)) ?
The integral of 1/(sqrt(2x-5)) is sqrt(2x-5)+C