What is the limit as x approaches 1-of ln(1-x^2) ?

The limit as x approaches 1-of ln(1-x^2) is -infinity

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limit as x approaches 1-of ln(1-x^2)

x \to 1 - lim (ln (1 - x^{2}))

- \infty

Solution steps

x \to 1 - lim (ln (1 - x^{2}))

Apply the Limit Chain Rule:

- \infty

= - \infty

x \to π lim (2^{c o s (x)})

x \to 5 - lim (\frac{x - 1}{2 x - 10})

x \to 0 lim (x - e^{x} + 1)

x \to - 2 lim (\frac{1}{4 - x ^{2}})

x \to 4 lim (\frac{3 x ^{2} - 17 x + 20}{4 x ^{2} - 25 + 36})

What is the limit as x approaches 1-of ln(1-x^2) ?
The limit as x approaches 1-of ln(1-x^2) is -infinity