What is (\partial)/(\partial x)(xcos(y^2)+yz) ?

The answer to (\partial)/(\partial x)(xcos(y^2)+yz) is cos(y^2)

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(\partial)/(\partial x)(xcos(y^2)+yz)

\frac{\partial}{\partial x} (x cos (y^{2}) + yz)

cos (y^{2})

Solution steps

\frac{\partial}{\partial x} (x cos (y^{2}) + yz)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x cos (y^{2})) + \frac{\partial}{\partial x} (yz)

\frac{\partial}{\partial x} (x cos (y^{2})) = cos (y^{2})

\frac{\partial}{\partial x} (yz) = 0

= cos (y^{2}) + 0

Simplify

= cos (y^{2})

\int \frac{x ^{2} + 1}{x ^{2} - 3} d x

x \to 0 lim (1 - x^{3})

\int \frac{x}{x ^{2_{- 1}}} d x

\int_{0}^{1} (3 x^{2} + 2 x + 1) d x

\frac{d}{d x} (\frac{2}{1 - x})

What is (\partial)/(\partial x)(xcos(y^2)+yz) ?
The answer to (\partial)/(\partial x)(xcos(y^2)+yz) is cos(y^2)