What is the derivative of 2x^2-4x+4 ?

The derivative of 2x^2-4x+4 is 4x-4

What is the first derivative of 2x^2-4x+4 ?

The first derivative of 2x^2-4x+4 is 4x-4

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\frac{d}{d x} (2 x^{2} - 4 x + 4)

4 x - 4

Solution steps

\frac{d}{d x} (2 x^{2} - 4 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (4) = 0

= 4 x - 4 + 0

Simplify

= 4 x - 4

\int \frac{ln ( x ^{2} )}{x ^{2}} d x

\frac{d}{d x} (arccos (\frac{7}{x}))

\int \frac{4}{3 x ^{2} 5 - 7 x ^{2}} d x

\frac{d}{d x} (\frac{4 x}{3 - cot ( x )})

f (x) = 6 ln (x)

What is the derivative of 2x^2-4x+4 ?
The derivative of 2x^2-4x+4 is 4x-4
What is the first derivative of 2x^2-4x+4 ?
The first derivative of 2x^2-4x+4 is 4x-4