What is the limit as x approaches infinity of-8(3/x) ?

The limit as x approaches infinity of-8(3/x) is 0

limit as x approaches infinity of-8(3/x)

x \to \infty lim (- 8 (\frac{3}{x}))

0

Solution steps

x \to \infty lim (- 8 \cdot \frac{3}{x})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - 8 \cdot 3 \cdot x \to \infty lim (\frac{1}{x})

Simplify

= - 24 \cdot x \to \infty lim (\frac{1}{x})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

With the exception of indeterminate form

= - 24 \cdot \frac{lim _{x \to \infty} ( 1 )}{lim _{x \to \infty} ( x )}

x \to \infty lim (1) = 1

x \to \infty lim (x) = \infty

= - 24 \cdot \frac{1}{\infty}

Simplify

- 24 \cdot \frac{1}{\infty} : 0

= 0

x \to 0 lim (\frac{5 ^{x} - 6 ^{x}}{x})

x \to 0 + lim (x ∣ x ∣)

x \to - \infty lim (2 (x))

x \to 0 + lim (x^{(x^{x})})

x \to 1 + lim (\frac{x ^{2}}{x - 1})

What is the limit as x approaches infinity of-8(3/x) ?
The limit as x approaches infinity of-8(3/x) is 0