What is the lhopital limit as x approaches infinity of xln(1+3/x) ?

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lhopital limit as x approaches infinity of xln(1+3/x)

lhopital

x \to \infty lim (x ln (1 + \frac{3}{x}))

3

Solution steps

x \to \infty lim (x ln (1 + \frac{3}{x}))

Solve using L'Hopital's Rule:

3

= 3

x \to - \infty lim (ln (0))

x \to π - lim (x cot (x))

x \to 1 lim (1 + 3 x - 1)

x \to \infty lim (\frac{1}{+ x})

x \to 3 - lim (\frac{4 x - 12}{x - 3})

What is the lhopital limit as x approaches infinity of xln(1+3/x) ?
The lhopital limit as x approaches infinity of xln(1+3/x) is 3