What is the derivative of e^x-2e^{-2x} ?

The derivative of e^x-2e^{-2x} is e^x+4e^{-2x}

What is the first derivative of e^x-2e^{-2x} ?

The first derivative of e^x-2e^{-2x} is e^x+4e^{-2x}

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\frac{d}{d x} (e^{x} - 2 e^{- 2 x})

e^{x} + 4 e^{- 2 x}

Solution steps

\frac{d}{d x} (e^{x} - 2 e^{- 2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) - \frac{d}{d x} (2 e^{- 2 x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (2 e^{- 2 x}) = - 4 e^{- 2 x}

= e^{x} - (- 4 e^{- 2 x})

Simplify

= e^{x} + 4 e^{- 2 x}

\int \frac{x ^{2} + 3 x + 7}{x} d x

d er i v a t i v e y = 5 x^{2} e^{2 x}

\frac{d}{d x} (\frac{x ( x ^{2} - 1 )}{x ^{2} + 1})

x \to 0 lim (x^{2} (sin (\frac{1}{x})))

\int x^{2} 3 + 2 x - x^{2} d x

What is the derivative of e^x-2e^{-2x} ?
The derivative of e^x-2e^{-2x} is e^x+4e^{-2x}
What is the first derivative of e^x-2e^{-2x} ?
The first derivative of e^x-2e^{-2x} is e^x+4e^{-2x}