integral of-e^xx

解答

\int - e^{x} x d x

- e^{x} x + e^{x} + C

求解步骤

\int - e^{x} x d x

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int e^{x} x d x

使用分布积分法

= - (e^{x} x - \int e^{x} d x)

\int e^{x} d x = e^{x}

= - (e^{x} x - e^{x})

化简

= - e^{x} x + e^{x}

解答补常数

= - e^{x} x + e^{x} + C

\int \frac{36}{1 + 36 x ^{2}} d x

y^{^{'}} = 1 - 2 y

d er i v a t i v e f (x) = \frac{x}{1 - ln ( x - 4 )}

t an g e n t f (x) = (1 + 3 x) (5 - 4 x), at x = 1

\frac{d}{d x} (a cos (a x))