integral from 1 to 2 of 1/x-x/4

Lösung

\int_{1}^{2} \frac{1}{x} - \frac{x}{4} d x

ln (2) - \frac{3}{8}

Dezimale

0.31814 \dots

Schritte zur Lösung

\int_{1}^{2} \frac{1}{x} - \frac{x}{4} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} \frac{1}{x} d x - \int_{1}^{2} \frac{x}{4} d x

\int_{1}^{2} \frac{1}{x} d x = ln (2)

\int_{1}^{2} \frac{x}{4} d x = \frac{3}{8}

= ln (2) - \frac{3}{8}

\int_{1}^{8} \frac{10}{x} d x

\int_{- 1}^{b} x^{2} (7 - x) d x

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\int_{- π}^{π} x sin (a x) d x

\int_{0}^{1} (x + \frac{1}{2})^{2} d x