integral from 0 to pi of sin(z)

Lösung

\int_{0}^{π} sin (z) d z

2

Schritte zur Lösung

\int_{0}^{π} sin (z) d z

Nutze das gemeinsame Integral :

\int sin (z) d z = - cos (z)

= [- cos (z)]_{0}^{π}

Berechne die Grenzen:

2

= 2

\int_{1}^{e} \frac{( x ^{2} + 1 ) ln ( x )}{x} d x

\int_{0}^{2} 0.5 d x

\int_{0}^{1} x^{2} 6 x + 9 d x

\int_{0}^{80} (1 - \frac{t}{80})^{a} d t

\int_{0}^{2 π} \frac{1 + cos ( 2 θ )}{2} d θ