integral from 1 to 4 of sqrt(x+1)

Lösung

\int_{1}^{4} x + 1 d x

\frac{10 5 - 4 2}{3}

Dezimale

5.56794 \dots

Schritte zur Lösung

\int_{1}^{4} x + 1 d x

Wende U-Substitution an

= \int_{2}^{5} u d u

Wende die Potenzregel an

= [\frac{2}{3} u^{\frac{3}{2}}]_{2}^{5}

Berechne die Grenzen:

\frac{10 5 - 4 2}{3}

= \frac{10 5 - 4 2}{3}

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