integral from 3 to 4 of (7/(x^2)-1)

Lösung

\int_{3}^{4} (\frac{7}{x ^{2}} - 1) d x

- \frac{5}{12}

Dezimale

- 0.41666 \dots

Schritte zur Lösung

\int_{3}^{4} \frac{7}{x ^{2}} - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{3}^{4} \frac{7}{x ^{2}} d x - \int_{3}^{4} 1 d x

\int_{3}^{4} \frac{7}{x ^{2}} d x = \frac{7}{12}

\int_{3}^{4} 1 d x = 1

= \frac{7}{12} - 1

Vereinfache

\frac{7}{12} - 1 : - \frac{5}{12}

= - \frac{5}{12}

\int_{0}^{2} 6 y^{2} - 2 y^{4} + y^{3} d y

\int_{0}^{1} (2 - 2 x)^{2} d x

\int_{0}^{π} (π - x) cos (n) x d x

\int_{0}^{\frac{5}{2}} 5 x - 2 x^{2} d x

\int_{0}^{5} e^{3 x + 1} d x