integral from 0 to 1 of e^y-1

Lösung

\int_{0}^{1} e^{y} - 1 d y

e - 2

Dezimale

0.71828 \dots

Schritte zur Lösung

\int_{0}^{1} e^{y} - 1 d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} e^{y} d y - \int_{0}^{1} 1 d y

\int_{0}^{1} e^{y} d y = e - 1

\int_{0}^{1} 1 d y = 1

= e - 1 - 1

Vereinfache

= e - 2

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