integral from 0 to 4 of x^3-3x^2+6

Lösung

\int_{0}^{4} x^{3} - 3 x^{2} + 6 d x

24

Schritte zur Lösung

\int_{0}^{4} x^{3} - 3 x^{2} + 6 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x^{3} d x - \int_{0}^{4} 3 x^{2} d x + \int_{0}^{4} 6 d x

\int_{0}^{4} x^{3} d x = 64

\int_{0}^{4} 3 x^{2} d x = 64

\int_{0}^{4} 6 d x = 24

= 64 - 64 + 24

Vereinfache

= 24

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