integral from 1 to 4 of 4/(x^3)

Lösung

\int_{1}^{4} \frac{4}{x ^{3}} d x

\frac{15}{8}

Dezimale

1.875

Schritte zur Lösung

\int_{1}^{4} \frac{4}{x ^{3}} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{1}^{4} \frac{1}{x ^{3}} d x

Wende die Potenzregel an

= 4 [- \frac{1}{2 x ^{2}}]_{1}^{4}

Berechne die Grenzen:

\frac{15}{32}

= 4 \cdot \frac{15}{32}

Vereinfache

= \frac{15}{8}

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