integral from 1 to 3 of (x^2)/4

Lösung

\int_{1}^{3} \frac{x ^{2}}{4} d x

\frac{13}{6}

Dezimale

2.16666 \dots

Schritte zur Lösung

\int_{1}^{3} \frac{x ^{2}}{4} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int_{1}^{3} x^{2} d x

Wende die Potenzregel an

= \frac{1}{4} [\frac{x ^{3}}{3}]_{1}^{3}

Berechne die Grenzen:

\frac{26}{3}

= \frac{1}{4} \cdot \frac{26}{3}

Vereinfache

= \frac{13}{6}

\int_{0}^{3} x^{3} - 10 x^{2} + 21 x d x

\int_{- 2}^{1} (- x^{2} + 7) d x

\int_{0}^{2} 2 x^{2} + 2 d x

\int_{- 3}^{x^{2}} (x - 5) (x^{2} + 1) d x

\int_{3}^{5} \frac{1}{x ^{2} - 6 x + 9} d x