integral from 0 to 2 of |sin(x)|

Lösung

\int_{0}^{2} ∣ sin (x) ∣ d x

- cos (2) + 1

Dezimale

1.41614 \dots

Schritte zur Lösung

\int_{0}^{2} ∣ sin (x) ∣ d x

Entferne die Extremwerte

= \int_{0}^{2} sin (x) d x

Nutze das gemeinsame Integral :

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{2}

Berechne die Grenzen:

- cos (2) + 1

= - cos (2) + 1

\int_{0}^{r} 1 d r

\int_{- 1}^{2} \frac{1}{3} x^{2} d x

\int_{0}^{l n (x)} (x e^{t^{2}}) d t

\int_{0}^{π} 4 sin (x) - 5 cos (x) d x

\int_{- 2}^{1} - x + 2 d x