integral from 0 to 4+2i of z

Lösung

\int_{0}^{4 + 2 i} z d z

\frac{( 2 i + 4 ) ^{2}}{2}

Schritte zur Lösung

\int_{0}^{4 + 2 i} z d z

Wende die Potenzregel an

= [\frac{z ^{2}}{2}]_{0}^{4 + 2 i}

Berechne die Grenzen:

\frac{( 2 i + 4 ) ^{2}}{2}

= \frac{( 2 i + 4 ) ^{2}}{2}

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