integral from 3 to 5 of 1/(sqrt(x-4))

Lösung

\int_{3}^{5} \frac{1}{x - 4} d x

- 2 i + 2

Schritte zur Lösung

\int_{3}^{5} \frac{1}{x - 4} d x

Bestimme unbestimmte (Singularitäts-)Punkte:

x = 4

Wenn

b, a < b < c, f (b) =

unbestimmt

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{3}^{4} \frac{1}{x - 4} d x + \int_{4}^{5} \frac{1}{x - 4} d x

\int_{3}^{4} \frac{1}{x - 4} d x = - 2 i

\int_{4}^{5} \frac{1}{x - 4} d x = 2

= - 2 i + 2

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