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Popular Calculus >

integral from 0 to 4 of x^2-8x

Solution

\int_{0}^{4} x^{2} - 8 x d x

Solution

- \frac{128}{3}

+1

Decimal

- 42.66666 \dots

Solution steps

\int_{0}^{4} x^{2} - 8 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x^{2} d x - \int_{0}^{4} 8 x d x

\int_{0}^{4} x^{2} d x = \frac{64}{3}

\int_{0}^{4} 8 x d x = 64

= \frac{64}{3} - 64

Simplify

\frac{64}{3} - 64 : - \frac{128}{3}

= - \frac{128}{3}

Graph

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\int_{- 2}^{1} x (x + 1)^{2} d x

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\int_{0}^{\frac{π}{2}} 243 sin (θ) d θ

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\int_{\frac{π}{12}}^{\frac{π}{6}} csc (3 x) d x

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\int_{5}^{6} f (4^{x}) 4^{x} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of x^2-8x ?
The integral from 0 to 4 of x^2-8x is -128/3