What is the integral from 1 to 9 of x^3 ?

The integral from 1 to 9 of x^3 is 1640

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integral from 1 to 9 of x^3

\int_{1}^{9} x^{3} d x

1640

Solution steps

\int_{1}^{9} x^{3} d x

Apply the Power Rule

= [\frac{x ^{4}}{4}]_{1}^{9}

Compute the boundaries:

1640

= 1640

\int_{1}^{9} \frac{1}{5 x + 4} d x

\int_{0}^{4} 2 x - \frac{1}{4} x^{2} d x

\int_{0}^{3} 6 x e^{x^{2}} d x

\int_{1}^{8} (3 x + 5) d x

\int_{2}^{5} x^{2} - 4 d x

What is the integral from 1 to 9 of x^3 ?
The integral from 1 to 9 of x^3 is 1640