What is the integral from 0 to 60 of x^{3/4} ?

The integral from 0 to 60 of x^{3/4} is (240*60^{3/4})/7

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integral from 0 to 60 of x^{3/4}

\int_{0}^{60} x^{\frac{3}{4}} d x

\frac{240 \cdot 6 0 ^{\frac{3}{4}}}{7}

Decimal

739.13988 \dots

Solution steps

\int_{0}^{60} x^{\frac{3}{4}} d x

Apply the Power Rule

= [\frac{4}{7} x^{\frac{7}{4}}]_{0}^{60}

Compute the boundaries:

\frac{240 \cdot 6 0 ^{\frac{3}{4}}}{7}

= \frac{240 \cdot 6 0 ^{\frac{3}{4}}}{7}

\int_{0}^{1} \frac{1 + 20 t}{1 + 4 t} d t

\int_{- 1}^{1} ∣ x + 1 ∣ d x

\int_{2}^{6} (2 x - 3) d x

\int_{0}^{1 - y} (6 y) d y

\int_{0}^{1} 5 - 6 x^{2} d x

What is the integral from 0 to 60 of x^{3/4} ?
The integral from 0 to 60 of x^{3/4} is (240*60^{3/4})/7