What is the integral from 1 to 3 of (x-2)^4 ?

The integral from 1 to 3 of (x-2)^4 is 2/5

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integral from 1 to 3 of (x-2)^4

\int_{1}^{3} (x - 2)^{4} d x

\frac{2}{5}

Decimal

0.4

Solution steps

\int_{1}^{3} (x - 2)^{4} d x

Apply u-substitution

= \int_{- 1}^{1} u^{4} d u

Apply the Power Rule

= [\frac{u ^{5}}{5}]_{- 1}^{1}

Compute the boundaries:

\frac{2}{5}

= \frac{2}{5}

\int_{0}^{1} e^{y} y d y

\int_{- 3}^{3} (x^{\frac{1}{3}}) d x

\int_{3}^{6} 1 0^{8} (\frac{x ^{2}}{3} + 1) d x

\int_{0}^{4} (4 x + 1) d x

\int_{- 2}^{\frac{i}{2}} (z^{2} + 1) d z

What is the integral from 1 to 3 of (x-2)^4 ?
The integral from 1 to 3 of (x-2)^4 is 2/5