What is the integral from-2 to 2 of (-x^2-4) ?

The integral from-2 to 2 of (-x^2-4) is -64/3

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integral from-2 to 2 of (-x^2-4)

\int_{- 2}^{2} (- x^{2} - 4) d x

- \frac{64}{3}

Decimal

- 21.33333 \dots

Solution steps

\int_{- 2}^{2} - x^{2} - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 2}^{2} x^{2} d x - \int_{- 2}^{2} 4 d x

\int_{- 2}^{2} x^{2} d x = \frac{16}{3}

\int_{- 2}^{2} 4 d x = 16

= - \frac{16}{3} - 16

Simplify

- \frac{16}{3} - 16 : - \frac{64}{3}

= - \frac{64}{3}

\int_{- 2}^{- 1} \frac{1}{1 + x} d x

\int_{0}^{1} (3 x + 1) d x

\int_{0}^{2} 2^{4 x} d x

\int_{0}^{1} t 3^{t^{2}} d t

\int_{0}^{4} (1 + 3 y - y^{2}) d y

What is the integral from-2 to 2 of (-x^2-4) ?
The integral from-2 to 2 of (-x^2-4) is -64/3