integral from 0 to 3 of (9-x^2)^{1/2}

Lösung

\int_{0}^{3} (9 - x^{2})^{\frac{1}{2}} d x

\frac{9 π}{4}

Dezimale

7.06858 \dots

Schritte zur Lösung

\int_{0}^{3} (9 - x^{2})^{\frac{1}{2}} d x

Trigonometrische Substitution anwenden

= \int_{0}^{\frac{π}{2}} 9 cos^{2} (u) d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int_{0}^{\frac{π}{2}} cos^{2} (u) d u

Umschreiben mit Hilfe von Trigonometrie-Identitäten

= 9 \cdot \int_{0}^{\frac{π}{2}} \frac{1 + cos ( 2 u )}{2} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \frac{1}{2} \cdot \int_{0}^{\frac{π}{2}} 1 + cos (2 u) d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 9 \cdot \frac{1}{2} (\int_{0}^{\frac{π}{2}} 1 d u + \int_{0}^{\frac{π}{2}} cos (2 u) d u)

\int_{0}^{\frac{π}{2}} 1 d u = \frac{π}{2}

\int_{0}^{\frac{π}{2}} cos (2 u) d u = 0

= 9 \cdot \frac{1}{2} (\frac{π}{2} + 0)

Vereinfache

9 \cdot \frac{1}{2} (\frac{π}{2} + 0) : \frac{9 π}{4}

= \frac{9 π}{4}

\int_{1}^{\infty} e^{\frac{1}{2} x} d x

\int_{0}^{1} 1 x 1 - x^{2} d x

\int_{0}^{\frac{π}{2}} cos (θ) + sin (θ) d θ

\int_{- 1}^{3} - 3 x^{2} + 6 x + 9 d x

\int_{0}^{\frac{π}{6}} \frac{1}{cos ^{2} ( 8 x )} d x