integral from b to a of 1/(x^2)

Lösung

\int_{b}^{a} \frac{1}{x ^{2}} d x

- \frac{1}{a} + \frac{1}{b}

Schritte zur Lösung

\int_{b}^{a} \frac{1}{x ^{2}} d x

Wende die Potenzregel an

= [- \frac{1}{x}]_{b}^{a}

Berechne die Grenzen:

- \frac{1}{a} + \frac{1}{b}

= - \frac{1}{a} + \frac{1}{b}

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