What is the integral from 0 to 2 of sqrt(4x) ?

The integral from 0 to 2 of sqrt(4x) is (8sqrt(2))/3

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integral from 0 to 2 of sqrt(4x)

\int_{0}^{2} 4 x d x

\frac{8 2}{3}

Decimal

3.77123 \dots

Solution steps

\int_{0}^{2} 4 x d x

Simplify

4 x : 2 x

= \int_{0}^{2} 2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{2} x d x

Apply the Power Rule

= 2 [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{2}

Compute the boundaries:

\frac{4 2}{3}

= 2 \cdot \frac{4 2}{3}

Simplify

= \frac{8 2}{3}

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What is the integral from 0 to 2 of sqrt(4x) ?
The integral from 0 to 2 of sqrt(4x) is (8sqrt(2))/3