What is the integral from-2 to 1 of-x^4-x^2-6x+8 ?

The integral from-2 to 1 of-x^4-x^2-6x+8 is 117/5

integral from-2 to 1 of-x^4-x^2-6x+8

\int_{- 2}^{1} - x^{4} - x^{2} - 6 x + 8 d x

\frac{117}{5}

Decimal

23.4

Solution steps

\int_{- 2}^{1} - x^{4} - x^{2} - 6 x + 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 2}^{1} x^{4} d x - \int_{- 2}^{1} x^{2} d x - \int_{- 2}^{1} 6 x d x + \int_{- 2}^{1} 8 d x

\int_{- 2}^{1} x^{4} d x = \frac{33}{5}

\int_{- 2}^{1} x^{2} d x = 3

\int_{- 2}^{1} 6 x d x = - 9

\int_{- 2}^{1} 8 d x = 24

= - \frac{33}{5} - 3 - (- 9) + 24

Simplify

- \frac{33}{5} - 3 - (- 9) + 24 : \frac{117}{5}

= \frac{117}{5}

\int_{- 2}^{2} - 3 x^{2} + 12 d x

\int_{0}^{2 π} cos (4 θ) d θ

\int_{1 - x^{2}}^{1 + x^{2}} e^{t^{2}} d t

\int_{4}^{9} 4 d x

\int_{- 1}^{0} x^{2} - x d x

What is the integral from-2 to 1 of-x^4-x^2-6x+8 ?
The integral from-2 to 1 of-x^4-x^2-6x+8 is 117/5