integral from 0 to 9 of |sqrt(x)-2|

Lösung

\int_{0}^{9} x - 2 d x

\frac{16}{3}

Dezimale

5.33333 \dots

Schritte zur Lösung

\int_{0}^{9} x - 2 d x

Entferne die Extremwerte

= \int_{0}^{4} - x + 2 d x + \int_{4}^{9} x - 2 d x

\int_{0}^{4} - x + 2 d x = \frac{8}{3}

\int_{4}^{9} x - 2 d x = \frac{8}{3}

= \frac{8}{3} + \frac{8}{3}

Vereinfache

\frac{8}{3} + \frac{8}{3} : \frac{16}{3}

= \frac{16}{3}

\int_{0}^{1} 7 x^{e} + 5 e^{x} d x

\int_{0}^{2 π} \frac{θ ^{2}}{2} d θ

\int_{0}^{10} x e^{- \frac{x}{12}} d x

\int_{0}^{1} 6 x^{2} - 6 x d x

\int_{1}^{2} 2 - t d t