integral from 0 to 64 of 1/(sqrt(x))

Lösung

\int_{0}^{64} \frac{1}{x} d x

16

Schritte zur Lösung

\int_{0}^{64} \frac{1}{x} d x

Wende die Potenzregel an

= [2 x^{\frac{1}{2}}]_{0}^{64}

Wende Radikal Regel an:

a^{\frac{1}{n}} = n a

= [2 x]_{0}^{64}

Berechne die Grenzen:

16

= 16

\int_{- 2}^{0} 4

\int_{0}^{3} π (4 5 x)^{2} d x

\int_{- 3}^{5} ∣ x - 1 ∣ d x

\int_{1}^{c} x ln (x) d x

\int_{0}^{2} r 4 - r^{2} - r^{2} d r