integral from 0 to sqrt(9-y^2 of)z

Lösung

\int_{0}^{9 - y^{2}} z d z

\frac{- y ^{2} + 9}{2}

Schritte zur Lösung

\int_{0}^{9 - y^{2}} z d z

Wende die Potenzregel an

= [\frac{z ^{2}}{2}]_{0}^{9 - y^{2}}

Berechne die Grenzen:

\frac{- y ^{2} + 9}{2}

= \frac{- y ^{2} + 9}{2}

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