integral from 0 to x^2 of t

解答

\int_{0}^{x^{2}} t d t

\frac{x ^{4}}{2}

求解步骤

\int_{0}^{x^{2}} t d t

使用幂法则

= [\frac{t ^{2}}{2}]_{0}^{x^{2}}

带入上下限计算后得:

\frac{x ^{4}}{2}

= \frac{x ^{4}}{2}

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