What is the integral from 4 to 9 of (1/(sqrt(x))) ?

The integral from 4 to 9 of (1/(sqrt(x))) is 2

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integral from 4 to 9 of (1/(sqrt(x)))

\int_{4}^{9} (\frac{1}{x}) d x

2

Solution steps

\int_{4}^{9} \frac{1}{x} d x

Apply the Power Rule

= [2 x^{\frac{1}{2}}]_{4}^{9}

Apply radical rule:

a^{\frac{1}{n}} = n a

= [2 x]_{4}^{9}

Compute the boundaries:

2

= 2

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What is the integral from 4 to 9 of (1/(sqrt(x))) ?
The integral from 4 to 9 of (1/(sqrt(x))) is 2