What is the integral from 0.5 to 1 of 1/(x^2) ?

The integral from 0.5 to 1 of 1/(x^2) is 1

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integral from 0.5 to 1 of 1/(x^2)

\int_{0.5}^{1} \frac{1}{x ^{2}} d x

1

Solution steps

\int_{0.5}^{1} \frac{1}{x ^{2}} d x

Apply the Power Rule

= [- \frac{1}{x}]_{0.5}^{1}

Compute the boundaries:

1

= 1

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\int_{0}^{1} x^{3} (1 - x) d x

\int_{- \infty}^{1} (\frac{1}{x ^{2}}) d x

\int_{1}^{7} 3 d x

\int_{0}^{\frac{π}{4}} sin^{2} (2 θ) d θ

What is the integral from 0.5 to 1 of 1/(x^2) ?
The integral from 0.5 to 1 of 1/(x^2) is 1