integral from 1 to 3 of (2x+2)

Lösung

\int_{1}^{3} (2 x + 2) d x

12

Schritte zur Lösung

\int_{1}^{3} 2 x + 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 2 x d x + \int_{1}^{3} 2 d x

\int_{1}^{3} 2 x d x = 8

\int_{1}^{3} 2 d x = 4

= 8 + 4

Vereinfache

= 12

\int_{0}^{3} x (x - 7) d x

\int_{1}^{2} \frac{d}{1} (3 + 5 t^{4}) d x

\int_{1}^{4} (\frac{3 x ^{2} + 9 x + 1}{x}) d x

\int_{2}^{3} \frac{2}{x ^{3} + x ^{2}} d x

\int_{- 2}^{2} (9 - ∣ x ∣^{3}) d x