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人気のある微分積分 >

integral from 1 to 2 of (1)

解

\int_{1}^{2} (1) d x

解

1

解答ステップ

\int_{1}^{2} 1 d x

定数の積分:

\int a d x = a x

= [1 \cdot x]_{1}^{2}

簡素化

= [x]_{1}^{2}

限度を計算する:

1

= 1

グラフ

人気の例

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\int_{- 4}^{6} (∣ x ∣) d x

integral from 2 to 3 of (2-x^2)

\int_{2}^{3} (2 - x^{2}) d x

integral from-1 to 2 of (x-(x^2-2))

\int_{- 1}^{2} (x - (x^{2} - 2)) d x

integral from 0 to 1 of 1/(sqrt(x)-1)

\int_{0}^{1} \frac{1}{x - 1} d x

integral from 1 to 5 of 5/(x^2)

\int_{1}^{5} \frac{5}{x ^{2}} d x