integral from 0 to 36 of sqrt(q)+10

Lösung

\int_{0}^{36} q + 10 d q

504

Schritte zur Lösung

\int_{0}^{36} q + 10 d q

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{36} q d q + \int_{0}^{36} 10 d q

\int_{0}^{36} q d q = 144

\int_{0}^{36} 10 d q = 360

= 144 + 360

Vereinfache

= 504

\int_{2}^{6} cos^{2} (x) d x

\int_{0}^{1} - 6 s d s

\int_{- 4}^{3} - x^{3} + 27 x + 140 - 6 x^{2} d x

\int_{0}^{2} x - x^{2} d x

\int_{0}^{\frac{π}{2}} sin^{5} (θ) d θ