integral from 0 to pi/2 of-6sin(x)

Lösung

\int_{0}^{\frac{π}{2}} - 6 sin (x) d x

- 6

Schritte zur Lösung

\int_{0}^{\frac{π}{2}} - 6 sin (x) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 6 \cdot \int_{0}^{\frac{π}{2}} sin (x) d x

Nutze das gemeinsame Integral :

\int sin (x) d x = - cos (x)

= - 6 [- cos (x)]_{0}^{\frac{π}{2}}

Berechne die Grenzen:

1

= - 6 \cdot 1

Vereinfache

= - 6

\int_{1}^{4} (x^{2} + 2) d x

\int_{- 1}^{0} \frac{x}{1 - x ^{2}} d x

\int_{0}^{2} 2 e^{x^{2} - 2 x} d x

\int_{0}^{\frac{π}{4}} t cos (2 t) d t

\int_{0}^{2} y 2 + 4 y^{2} d y