integral from-1 to 2 of 8-x^2-x

Lösung

\int_{- 1}^{2} 8 - x^{2} - x d x

\frac{39}{2}

Dezimale

19.5

Schritte zur Lösung

\int_{- 1}^{2} 8 - x^{2} - x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} 8 d x - \int_{- 1}^{2} x^{2} d x - \int_{- 1}^{2} x d x

\int_{- 1}^{2} 8 d x = 24

\int_{- 1}^{2} x^{2} d x = 3

\int_{- 1}^{2} x d x = \frac{3}{2}

= 24 - 3 - \frac{3}{2}

Vereinfache

24 - 3 - \frac{3}{2} : \frac{39}{2}

= \frac{39}{2}

\int_{- 2}^{2} 1 - \frac{x ^{2}}{4} d x

\int_{- 2}^{1} 2 x^{2} d x

\int_{- 1}^{1} (x^{2} - x) (x + 1) d x

\int_{0}^{3} - 10 x d x

\int_{0}^{5} t e^{- s t} d t