integral from 1 to 2 of 8x-16

Lösung

\int_{1}^{2} 8 x - 16 d x

- 4

Schritte zur Lösung

\int_{1}^{2} 8 x - 16 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 8 x d x - \int_{1}^{2} 16 d x

\int_{1}^{2} 8 x d x = 12

\int_{1}^{2} 16 d x = 16

= 12 - 16

Vereinfache

= - 4

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