integral from 2 to 4 of 1/(x-2)

Lösung

\int_{2}^{4} \frac{1}{x - 2} d x

divergiert

Schritte zur Lösung

\int_{2}^{4} \frac{1}{x - 2} d x

Wende U-Substitution an

= \int_{0}^{2} \frac{1}{u} d u

Nutze das gemeinsame Integral :

\int \frac{1}{u} d u = ln (∣ u ∣)

= [ln ∣ u ∣]_{0}^{2}

Berechne die Grenzen:

divergiert

= divergiert

\int_{- 3}^{- 2} x^{2} + 5 x + 6 d x

\int_{0}^{\frac{π}{3}} (4 sec^{2} (x)) d x

\int_{1}^{9} \frac{9}{x} - \frac{x}{9} d x

\int_{0}^{l} x l sin (\frac{nπ x}{l}) d x

\int_{1}^{4} 3^{3 x} d x