integral from 1 to 5 of x^2-x-6

Lösung

\int_{1}^{5} x^{2} - x - 6 d x

\frac{16}{3}

Dezimale

5.33333 \dots

Schritte zur Lösung

\int_{1}^{5} x^{2} - x - 6 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{5} x^{2} d x - \int_{1}^{5} x d x - \int_{1}^{5} 6 d x

\int_{1}^{5} x^{2} d x = \frac{124}{3}

\int_{1}^{5} x d x = 12

\int_{1}^{5} 6 d x = 24

= \frac{124}{3} - 12 - 24

Vereinfache

\frac{124}{3} - 12 - 24 : \frac{16}{3}

= \frac{16}{3}

\int_{1}^{8} \frac{4}{3} x^{\frac{1}{3}} d x

\int_{0}^{1} (5 x^{2} - 8 x + 6) d x

\int_{1}^{2} k x d x

\int_{0}^{2.8} 3 3 x + 4 d x

\int_{0}^{1} e^{x} + x^{2} d x