integral from 0 to 1 of e^x2x

Lösung

\int_{0}^{1} e^{x} 2 x d x

2

Schritte zur Lösung

\int_{0}^{1} e^{x} \cdot 2 x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{1} e^{x} x d x

Wende die partielle Integration an

= 2 [e^{x} x - \int e^{x} d x]_{0}^{1}

\int e^{x} d x = e^{x}

= 2 [e^{x} x - e^{x}]_{0}^{1}

Berechne die Grenzen:

1

= 2 \cdot 1

Vereinfache

= 2

\int_{1}^{3} \frac{( x ^{3} - 1 )}{x ^{4}} d x

\int_{1}^{2} ρ^{2} d ρ

\int_{- 2}^{2} x^{2} - 3 d x

\int_{1}^{3} \frac{1}{x ^{6}} d x

\int_{1}^{4} (\frac{3}{x ^{2}}) d x