integral from 0 to 20 of 840-42x

Lösung

\int_{0}^{20} 840 - 42 x d x

8400

Schritte zur Lösung

\int_{0}^{20} 840 - 42 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{20} 840 d x - \int_{0}^{20} 42 x d x

\int_{0}^{20} 840 d x = 16800

\int_{0}^{20} 42 x d x = 8400

= 16800 - 8400

Vereinfache

= 8400

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