What is the integral from 1 to infinity of xe^{-x/2} ?

The integral from 1 to infinity of xe^{-x/2} is 6/(e^{1/2)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 1 to infinity of xe^{-x/2}

\int_{1}^{\infty} x e^{- \frac{x}{2}} d x

\frac{6}{e ^{\frac{1}{2}}}

Decimal

3.63918 \dots

Solution steps

\int_{1}^{\infty} x e^{- \frac{x}{2}} d x

Compute the indefinite integral:

\int x e^{- \frac{x}{2}} d x = - 2 e^{- \frac{x}{2}} x - 4 e^{- \frac{x}{2}} + C

Compute the boundaries:

\int_{1}^{\infty} x e^{- \frac{x}{2}} d x = 0 - (- \frac{6}{e ^{\frac{1}{2}}})

= 0 - (- \frac{6}{e ^{\frac{1}{2}}})

Simplify

= \frac{6}{e ^{\frac{1}{2}}}

What is the integral from 1 to infinity of xe^{-x/2} ?
The integral from 1 to infinity of xe^{-x/2} is 6/(e^{1/2)}