integral from 1 to 2 of (3x^2+4x+1)

Lösung

\int_{1}^{2} (3 x^{2} + 4 x + 1) d x

14

Schritte zur Lösung

\int_{1}^{2} 3 x^{2} + 4 x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 3 x^{2} d x + \int_{1}^{2} 4 x d x + \int_{1}^{2} 1 d x

\int_{1}^{2} 3 x^{2} d x = 7

\int_{1}^{2} 4 x d x = 6

\int_{1}^{2} 1 d x = 1

= 7 + 6 + 1

Vereinfache

= 14

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